Base | Representation |
---|---|
bin | 101110111101010101111101… |
… | …1100000010010010010011111 |
3 | 2000011111022102000111211112101 |
4 | 1131322223323200102102133 |
5 | 413114412401421313210 |
6 | 4022253040220145531 |
7 | 153000652252634122 |
oct | 13572537340222237 |
9 | 2004438360454471 |
10 | 413051224401055 |
11 | 10a67a049a51039 |
12 | 3a3b01173982a7 |
13 | 14962742831a46 |
14 | 73ddb008423b9 |
15 | 32b46248b5a3a |
hex | 177aafb81249f |
413051224401055 has 8 divisors (see below), whose sum is σ = 495749150452512. Its totient is φ = 330382525406688.
The previous prime is 413051224401041. The next prime is 413051224401061. The reversal of 413051224401055 is 550104422150314.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-413051224401055 is a prime.
It is a super-2 number, since 2×4130512244010552 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7306733179 + ... + 7306789708.
It is an arithmetic number, because the mean of its divisors is an integer number (61968643806564).
Almost surely, 2413051224401055 is an apocalyptic number.
413051224401055 is a deficient number, since it is larger than the sum of its proper divisors (82697926051457).
413051224401055 is a wasteful number, since it uses less digits than its factorization.
413051224401055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14613528545.
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 413051224401055 its reverse (550104422150314), we get a palindrome (963155646551369).
The spelling of 413051224401055 in words is "four hundred thirteen trillion, fifty-one billion, two hundred twenty-four million, four hundred one thousand, fifty-five".
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