Base | Representation |
---|---|
bin | 10010110010001000110011… |
… | …01000000000001001101111 |
3 | 12102020201202120000220120220 |
4 | 21121010121220000021233 |
5 | 20403220401340334130 |
6 | 223503152010142423 |
7 | 11462124431320515 |
oct | 1131043150001157 |
9 | 172221676026526 |
10 | 41305130402415 |
11 | 12185453320560 |
12 | 4771264721a13 |
13 | 1a0809854a479 |
14 | a2b27118c4b5 |
15 | 4b9694256410 |
hex | 259119a0026f |
41305130402415 has 32 divisors (see below), whose sum is σ = 72734247357696. Its totient is φ = 19849502184960.
The previous prime is 41305130402387. The next prime is 41305130402423. The reversal of 41305130402415 is 51420403150314.
It is not a de Polignac number, because 41305130402415 - 29 = 41305130401903 is a prime.
It is a super-2 number, since 2×413051304024152 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1107654469 + ... + 1107691758.
It is an arithmetic number, because the mean of its divisors is an integer number (2272945229928).
Almost surely, 241305130402415 is an apocalyptic number.
41305130402415 is a deficient number, since it is larger than the sum of its proper divisors (31429116955281).
41305130402415 is a wasteful number, since it uses less digits than its factorization.
41305130402415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2215346359.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 41305130402415 its reverse (51420403150314), we get a palindrome (92725533552729).
The spelling of 41305130402415 in words is "forty-one trillion, three hundred five billion, one hundred thirty million, four hundred two thousand, four hundred fifteen".
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