Base | Representation |
---|---|
bin | 1100000001011110111… |
… | …01000100111100100001 |
3 | 1110111022120000101202222 |
4 | 12000233131010330201 |
5 | 23232023412341001 |
6 | 513440445320425 |
7 | 41563216443464 |
oct | 6005735047441 |
9 | 1414276011688 |
10 | 413113012001 |
11 | 14a2225863a8 |
12 | 68092866115 |
13 | 2cc5825b341 |
14 | 15dcd9492db |
15 | ab2cc2061b |
hex | 602f744f21 |
413113012001 has 2 divisors, whose sum is σ = 413113012002. Its totient is φ = 413113012000.
The previous prime is 413113011989. The next prime is 413113012031. The reversal of 413113012001 is 100210311314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 343442881600 + 69670130401 = 586040^2 + 263951^2 .
It is a cyclic number.
It is not a de Polignac number, because 413113012001 - 26 = 413113011937 is a prime.
It is a super-4 number, since 4×4131130120014 (a number of 48 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (413113012031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206556506000 + 206556506001.
It is an arithmetic number, because the mean of its divisors is an integer number (206556506001).
Almost surely, 2413113012001 is an apocalyptic number.
It is an amenable number.
413113012001 is a deficient number, since it is larger than the sum of its proper divisors (1).
413113012001 is an equidigital number, since it uses as much as digits as its factorization.
413113012001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 413113012001 its reverse (100210311314), we get a palindrome (513323323315).
The spelling of 413113012001 in words is "four hundred thirteen billion, one hundred thirteen million, twelve thousand, one".
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