Base | Representation |
---|---|
bin | 10010110010100100000101… |
… | …11010100100011010011111 |
3 | 12102022010120122011221222221 |
4 | 21121102002322210122133 |
5 | 20403440403113412403 |
6 | 223514013512050211 |
7 | 11463153466055452 |
oct | 1131220272443237 |
9 | 172263518157887 |
10 | 41319781779103 |
11 | 12190691678733 |
12 | 4774073393967 |
13 | 1a09591aa2b29 |
14 | a2bc60d83499 |
15 | 4b9c50654dbd |
hex | 259482ea469f |
41319781779103 has 4 divisors (see below), whose sum is σ = 41385264793648. Its totient is φ = 41254298764560.
The previous prime is 41319781779019. The next prime is 41319781779127. The reversal of 41319781779103 is 30197718791314.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41319781779103 - 233 = 41311191844511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41319781779403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32741506326 + ... + 32741507587.
It is an arithmetic number, because the mean of its divisors is an integer number (10346316198412).
Almost surely, 241319781779103 is an apocalyptic number.
41319781779103 is a deficient number, since it is larger than the sum of its proper divisors (65483014545).
41319781779103 is an equidigital number, since it uses as much as digits as its factorization.
41319781779103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65483014544.
The product of its (nonzero) digits is 8001504, while the sum is 61.
The spelling of 41319781779103 in words is "forty-one trillion, three hundred nineteen billion, seven hundred eighty-one million, seven hundred seventy-nine thousand, one hundred three".
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