Base | Representation |
---|---|
bin | 1100000001101001100… |
… | …00101100010101000101 |
3 | 1110111112202112111102012 |
4 | 12000310300230111011 |
5 | 23232214210241013 |
6 | 513453345424005 |
7 | 41565350250641 |
oct | 6006460542505 |
9 | 1414482474365 |
10 | 413202040133 |
11 | 14a268863573 |
12 | 680b863b005 |
13 | 2cc7082cacc |
14 | 15ddb6c1c21 |
15 | ab359591a8 |
hex | 6034c2c545 |
413202040133 has 2 divisors, whose sum is σ = 413202040134. Its totient is φ = 413202040132.
The previous prime is 413202040123. The next prime is 413202040169. The reversal of 413202040133 is 331040202314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 305103779044 + 108098261089 = 552362^2 + 328783^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-413202040133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 413202040099 and 413202040108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413202040123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206601020066 + 206601020067.
It is an arithmetic number, because the mean of its divisors is an integer number (206601020067).
Almost surely, 2413202040133 is an apocalyptic number.
It is an amenable number.
413202040133 is a deficient number, since it is larger than the sum of its proper divisors (1).
413202040133 is an equidigital number, since it uses as much as digits as its factorization.
413202040133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 413202040133 its reverse (331040202314), we get a palindrome (744242242447).
The spelling of 413202040133 in words is "four hundred thirteen billion, two hundred two million, forty thousand, one hundred thirty-three".
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