Base | Representation |
---|---|
bin | 10010110010100101010100… |
… | …10101110001100001111111 |
3 | 12102022012021201210202021022 |
4 | 21121102222111301201333 |
5 | 20403443231431102033 |
6 | 223514203301054355 |
7 | 11463206050202021 |
oct | 1131225225614177 |
9 | 172265251722238 |
10 | 41320443222143 |
11 | 121909a0a82678 |
12 | 47742189b73bb |
13 | 1a09668b32447 |
14 | a2bcc4b62011 |
15 | 4b9c8d75d098 |
hex | 2594aa57187f |
41320443222143 has 4 divisors (see below), whose sum is σ = 41320498296960. Its totient is φ = 41320388147328.
The previous prime is 41320443222139. The next prime is 41320443222187. The reversal of 41320443222143 is 34122234402314.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 41320443222143 - 22 = 41320443222139 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41320443282143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26396255 + ... + 27917792.
It is an arithmetic number, because the mean of its divisors is an integer number (10330124574240).
Almost surely, 241320443222143 is an apocalyptic number.
41320443222143 is a deficient number, since it is larger than the sum of its proper divisors (55074817).
41320443222143 is an equidigital number, since it uses as much as digits as its factorization.
41320443222143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55074816.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 41320443222143 its reverse (34122234402314), we get a palindrome (75442677624457).
The spelling of 41320443222143 in words is "forty-one trillion, three hundred twenty billion, four hundred forty-three million, two hundred twenty-two thousand, one hundred forty-three".
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