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413311242341 is a prime number
BaseRepresentation
bin1100000001110110100…
…01010001000001100101
31110111211101000112200102
412000323101101001211
523232430134223331
6513512250153445
741601144410504
oct6007321210145
91414741015612
10413311242341
1114a31446a828
1268129122885
132cc8a345cba
141600bdca83b
15ab4032a4cb
hex603b451065

413311242341 has 2 divisors, whose sum is σ = 413311242342. Its totient is φ = 413311242340.

The previous prime is 413311242319. The next prime is 413311242343. The reversal of 413311242341 is 143242113314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 413307552100 + 3690241 = 642890^2 + 1921^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-413311242341 is a prime.

Together with 413311242343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (413311242343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206655621170 + 206655621171.

It is an arithmetic number, because the mean of its divisors is an integer number (206655621171).

Almost surely, 2413311242341 is an apocalyptic number.

It is an amenable number.

413311242341 is a deficient number, since it is larger than the sum of its proper divisors (1).

413311242341 is an equidigital number, since it uses as much as digits as its factorization.

413311242341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 29.

Adding to 413311242341 its reverse (143242113314), we get a palindrome (556553355655).

The spelling of 413311242341 in words is "four hundred thirteen billion, three hundred eleven million, two hundred forty-two thousand, three hundred forty-one".