Base | Representation |
---|---|
bin | 1100000001111000000… |
… | …11001111000000111011 |
3 | 1110111212021200001002022 |
4 | 12000330003033000323 |
5 | 23232442012410212 |
6 | 513513435025055 |
7 | 41601363635063 |
oct | 6007403170073 |
9 | 1414767601068 |
10 | 413324341307 |
11 | 14a3208a7219 |
12 | 6813159b18b |
13 | 2cc8cc81277 |
14 | 1600da3a3a3 |
15 | ab41566772 |
hex | 603c0cf03b |
413324341307 has 4 divisors (see below), whose sum is σ = 413468812656. Its totient is φ = 413179869960.
The previous prime is 413324341271. The next prime is 413324341327. The reversal of 413324341307 is 703143423314.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 413324341307 - 210 = 413324340283 is a prime.
It is a super-2 number, since 2×4133243413072 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (413324341327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72231383 + ... + 72237104.
It is an arithmetic number, because the mean of its divisors is an integer number (103367203164).
Almost surely, 2413324341307 is an apocalyptic number.
413324341307 is a deficient number, since it is larger than the sum of its proper divisors (144471349).
413324341307 is a wasteful number, since it uses less digits than its factorization.
413324341307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 144471348.
The product of its (nonzero) digits is 72576, while the sum is 35.
The spelling of 413324341307 in words is "four hundred thirteen billion, three hundred twenty-four million, three hundred forty-one thousand, three hundred seven".
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