Base | Representation |
---|---|
bin | 1100000001111000110… |
… | …00111100101100111111 |
3 | 1110111212200101020021012 |
4 | 12000330120330230333 |
5 | 23232444442032341 |
6 | 513514201025435 |
7 | 41601463213235 |
oct | 6007430745477 |
9 | 1414780336235 |
10 | 413330033471 |
11 | 14a324034893 |
12 | 6813348527b |
13 | 2cc911c5104 |
14 | 160106bc955 |
15 | ab41cdd0eb |
hex | 603c63cb3f |
413330033471 has 2 divisors, whose sum is σ = 413330033472. Its totient is φ = 413330033470.
The previous prime is 413330033461. The next prime is 413330033503. The reversal of 413330033471 is 174330033314.
It is an a-pointer prime, because the next prime (413330033503) can be obtained adding 413330033471 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 413330033471 - 230 = 412256291647 is a prime.
It is a super-3 number, since 3×4133300334713 (a number of 36 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413330033401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206665016735 + 206665016736.
It is an arithmetic number, because the mean of its divisors is an integer number (206665016736).
Almost surely, 2413330033471 is an apocalyptic number.
413330033471 is a deficient number, since it is larger than the sum of its proper divisors (1).
413330033471 is an equidigital number, since it uses as much as digits as its factorization.
413330033471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27216, while the sum is 32.
Adding to 413330033471 its reverse (174330033314), we get a palindrome (587660066785).
The spelling of 413330033471 in words is "four hundred thirteen billion, three hundred thirty million, thirty-three thousand, four hundred seventy-one".
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