Base | Representation |
---|---|
bin | 111100001010001000000… |
… | …000000001000001101111 |
3 | 112122012200101001121212001 |
4 | 330022020000001001233 |
5 | 1020213003300304320 |
6 | 12443052445353131 |
7 | 604450241200351 |
oct | 74121000010157 |
9 | 15565611047761 |
10 | 4134040244335 |
11 | 1354266a42101 |
12 | 5692558687a7 |
13 | 23cab8a42791 |
14 | 1041352370d1 |
15 | 7280889320a |
hex | 3c28800106f |
4134040244335 has 8 divisors (see below), whose sum is σ = 4966086787056. Its totient is φ = 3303739866240.
The previous prime is 4134040244293. The next prime is 4134040244353. The reversal of 4134040244335 is 5334420404314.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 4134040244335 - 213 = 4134040236143 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4134040244294 and 4134040244303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 436535946 + ... + 436545415.
It is an arithmetic number, because the mean of its divisors is an integer number (620760848382).
Almost surely, 24134040244335 is an apocalyptic number.
4134040244335 is a deficient number, since it is larger than the sum of its proper divisors (832046542721).
4134040244335 is an equidigital number, since it uses as much as digits as its factorization.
4134040244335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 873082313.
The product of its (nonzero) digits is 276480, while the sum is 37.
Adding to 4134040244335 its reverse (5334420404314), we get a palindrome (9468460648649).
The spelling of 4134040244335 in words is "four trillion, one hundred thirty-four billion, forty million, two hundred forty-four thousand, three hundred thirty-five".
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