413405313001 has 4 divisors (see below), whose sum is σ = 413439945604. Its totient is φ = 413370680400.

The previous prime is 413405312959. The next prime is 413405313007. The reversal of 413405313001 is 100313504314.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 272145848976 + 141259464025 = 521676^2 + 375845^2 .

It is a cyclic number.

It is not a de Polignac number, because 413405313001 - 2²³ = 413396924393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (413405313007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17298390 + ... + 17322271.

It is an arithmetic number, because the mean of its divisors is an integer number (103359986401).

Almost surely, 2^413405313001 is an apocalyptic number.

It is an amenable number.

413405313001 is a deficient number, since it is larger than the sum of its proper divisors (34632603).

413405313001 is a wasteful number, since it uses less digits than its factorization.

413405313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34632602.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 413405313001 its reverse (100313504314), we get a palindrome (513718817315).

The spelling of 413405313001 in words is "four hundred thirteen billion, four hundred five million, three hundred thirteen thousand, one".