Base | Representation |
---|---|
bin | 111100001010010010111… |
… | …100111111100100010101 |
3 | 112122020011011211110000121 |
4 | 330022102330333210111 |
5 | 1020213342321020201 |
6 | 12443123012111541 |
7 | 604454632124062 |
oct | 74122274774425 |
9 | 15566134743017 |
10 | 4134224001301 |
11 | 1354350740469 |
12 | 5692a73055b1 |
13 | 23cb17b30704 |
14 | 1041517cbc69 |
15 | 72819a8e9a1 |
hex | 3c292f3f915 |
4134224001301 has 2 divisors, whose sum is σ = 4134224001302. Its totient is φ = 4134224001300.
The previous prime is 4134224001289. The next prime is 4134224001379. The reversal of 4134224001301 is 1031004224314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3799965422500 + 334258578801 = 1949350^2 + 578151^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4134224001301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4134224002301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067112000650 + 2067112000651.
It is an arithmetic number, because the mean of its divisors is an integer number (2067112000651).
Almost surely, 24134224001301 is an apocalyptic number.
It is an amenable number.
4134224001301 is a deficient number, since it is larger than the sum of its proper divisors (1).
4134224001301 is an equidigital number, since it uses as much as digits as its factorization.
4134224001301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4134224001301 its reverse (1031004224314), we get a palindrome (5165228225615).
The spelling of 4134224001301 in words is "four trillion, one hundred thirty-four billion, two hundred twenty-four million, one thousand, three hundred one".
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