Base | Representation |
---|---|
bin | 111100001010011001100… |
… | …000101001001101110111 |
3 | 112122020102211211110220102 |
4 | 330022121200221031313 |
5 | 1020214104001311411 |
6 | 12443141542024315 |
7 | 604460436153605 |
oct | 74123140511567 |
9 | 15566384743812 |
10 | 4134334010231 |
11 | 13543a7848837 |
12 | 56931811809b |
13 | 23cb34869b59 |
14 | 104162266875 |
15 | 7282456ed3b |
hex | 3c299829377 |
4134334010231 has 4 divisors (see below), whose sum is σ = 4134965116464. Its totient is φ = 4133702904000.
The previous prime is 4134334010173. The next prime is 4134334010243. The reversal of 4134334010231 is 1320104334314.
It is a happy number.
4134334010231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4134334010231 - 26 = 4134334010167 is a prime.
It is a super-2 number, since 2×41343340102312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4134334010194 and 4134334010203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4134334012231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 315543290 + ... + 315556391.
It is an arithmetic number, because the mean of its divisors is an integer number (1033741279116).
Almost surely, 24134334010231 is an apocalyptic number.
4134334010231 is a deficient number, since it is larger than the sum of its proper divisors (631106233).
4134334010231 is an equidigital number, since it uses as much as digits as its factorization.
4134334010231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 631106232.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 4134334010231 its reverse (1320104334314), we get a palindrome (5454438344545).
The spelling of 4134334010231 in words is "four trillion, one hundred thirty-four billion, three hundred thirty-four million, ten thousand, two hundred thirty-one".
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