Base | Representation |
---|---|
bin | 111100001010100101111… |
… | …111000110010001000001 |
3 | 112122020222102200112002212 |
4 | 330022211333012101001 |
5 | 1020220021042221004 |
6 | 12443214420151505 |
7 | 604465560234545 |
oct | 74124577062101 |
9 | 15566872615085 |
10 | 4134543320129 |
11 | 13544a4a0a422 |
12 | 569376238595 |
13 | 23cb69033871 |
14 | 104181d8da25 |
15 | 72837b1796e |
hex | 3c2a5fc6441 |
4134543320129 has 2 divisors, whose sum is σ = 4134543320130. Its totient is φ = 4134543320128.
The previous prime is 4134543320101. The next prime is 4134543320231. The reversal of 4134543320129 is 9210233454314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4014120439729 + 120422880400 = 2003527^2 + 347020^2 .
It is a cyclic number.
It is not a de Polignac number, because 4134543320129 - 28 = 4134543319873 is a prime.
It is not a weakly prime, because it can be changed into another prime (4134543020129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067271660064 + 2067271660065.
It is an arithmetic number, because the mean of its divisors is an integer number (2067271660065).
Almost surely, 24134543320129 is an apocalyptic number.
It is an amenable number.
4134543320129 is a deficient number, since it is larger than the sum of its proper divisors (1).
4134543320129 is an equidigital number, since it uses as much as digits as its factorization.
4134543320129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 41.
The spelling of 4134543320129 in words is "four trillion, one hundred thirty-four billion, five hundred forty-three million, three hundred twenty thousand, one hundred twenty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •