4134543320231 has 2 divisors, whose sum is σ = 4134543320232. Its totient is φ = 4134543320230.

The previous prime is 4134543320129. The next prime is 4134543320233. The reversal of 4134543320231 is 1320233454314.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4134543320231 is a prime.

It is a super-2 number, since 2×4134543320231² (a number of 26 digits) contains 22 as substring.

Together with 4134543320233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4134543320191 and 4134543320200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4134543320233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067271660115 + 2067271660116.

It is an arithmetic number, because the mean of its divisors is an integer number (2067271660116).

Almost surely, 2^{4134543320231} is an apocalyptic number.

4134543320231 is a deficient number, since it is larger than the sum of its proper divisors (1).

4134543320231 is an equidigital number, since it uses as much as digits as its factorization.

4134543320231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 4134543320231 its reverse (1320233454314), we get a palindrome (5454776774545).

The spelling of 4134543320231 in words is "four trillion, one hundred thirty-four billion, five hundred forty-three million, three hundred twenty thousand, two hundred thirty-one".