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4134543320203 = 15367932690371
BaseRepresentation
bin111100001010100101111…
…111000110010010001011
3112122020222102200112012121
4330022211333012102023
51020220021042221303
612443214420152111
7604465560235012
oct74124577062213
915566872615177
104134543320203
1113544a4a0a48a
12569376238637
1323cb690338ca
14104181d8da79
1572837b179bd
hex3c2a5fc648b

4134543320203 has 4 divisors (see below), whose sum is σ = 4134547547368. Its totient is φ = 4134539093040.

The previous prime is 4134543320129. The next prime is 4134543320231. The reversal of 4134543320203 is 3020233454314.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 4134543320203 - 229 = 4134006449291 is a prime.

It is a super-2 number, since 2×41345433202032 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4134543320233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191608 + ... + 2881978.

It is an arithmetic number, because the mean of its divisors is an integer number (1033636886842).

Almost surely, 24134543320203 is an apocalyptic number.

4134543320203 is a deficient number, since it is larger than the sum of its proper divisors (4227165).

4134543320203 is a wasteful number, since it uses less digits than its factorization.

4134543320203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4227164.

The product of its (nonzero) digits is 103680, while the sum is 34.

Adding to 4134543320203 its reverse (3020233454314), we get a palindrome (7154776774517).

The spelling of 4134543320203 in words is "four trillion, one hundred thirty-four billion, five hundred forty-three million, three hundred twenty thousand, two hundred three".

Divisors: 1 1536793 2690371 4134543320203