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4138871109281 is a prime number
BaseRepresentation
bin111100001110100111111…
…100010011011010100001
3112122200011001011222201222
4330032213330103122201
51020302402000444111
612445212055504425
7605011040650616
oct74164774233241
915580131158658
104138871109281
111356315928477
1256a183688115
132403a883294c
14104472a6c50d
15729dca3a7db
hex3c3a7f136a1

4138871109281 has 2 divisors, whose sum is σ = 4138871109282. Its totient is φ = 4138871109280.

The previous prime is 4138871109271. The next prime is 4138871109283. The reversal of 4138871109281 is 1829011788314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3460251030625 + 678620078656 = 1860175^2 + 823784^2 .

It is a cyclic number.

It is not a de Polignac number, because 4138871109281 - 214 = 4138871092897 is a prime.

It is a super-2 number, since 2×41388711092812 (a number of 26 digits) contains 22 as substring.

Together with 4138871109283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4138871109283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2069435554640 + 2069435554641.

It is an arithmetic number, because the mean of its divisors is an integer number (2069435554641).

Almost surely, 24138871109281 is an apocalyptic number.

It is an amenable number.

4138871109281 is a deficient number, since it is larger than the sum of its proper divisors (1).

4138871109281 is an equidigital number, since it uses as much as digits as its factorization.

4138871109281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 774144, while the sum is 53.

The spelling of 4138871109281 in words is "four trillion, one hundred thirty-eight billion, eight hundred seventy-one million, one hundred nine thousand, two hundred eighty-one".