Base | Representation |
---|---|
bin | 1100000011000111000… |
… | …00011111110000100101 |
3 | 1110120120102022012221001 |
4 | 12001203200133300211 |
5 | 23240320444322433 |
6 | 514103243353301 |
7 | 41623652455231 |
oct | 6014340376045 |
9 | 1416512265831 |
10 | 413986323493 |
11 | 14a63053a236 |
12 | 68297222831 |
13 | 3006716c0c2 |
14 | 160739195c1 |
15 | ab7e72957d |
hex | 606381fc25 |
413986323493 has 2 divisors, whose sum is σ = 413986323494. Its totient is φ = 413986323492.
The previous prime is 413986323481. The next prime is 413986323557. The reversal of 413986323493 is 394323689314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 400558612609 + 13427710884 = 632897^2 + 115878^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-413986323493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413986323433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206993161746 + 206993161747.
It is an arithmetic number, because the mean of its divisors is an integer number (206993161747).
Almost surely, 2413986323493 is an apocalyptic number.
It is an amenable number.
413986323493 is a deficient number, since it is larger than the sum of its proper divisors (1).
413986323493 is an equidigital number, since it uses as much as digits as its factorization.
413986323493 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10077696, while the sum is 55.
The spelling of 413986323493 in words is "four hundred thirteen billion, nine hundred eighty-six million, three hundred twenty-three thousand, four hundred ninety-three".
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