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41531504505431 is a prime number
BaseRepresentation
bin10010111000101110011101…
…00100101011001001010111
312110001101001221211211212112
421130113032210223021113
520420423010123133211
6224155150524541235
711514360253412243
oct1134271644531127
9173041057754775
1041531504505431
1112262459629706
1247a91009b181b
131a23533985055
14a381c7d07423
154c04e2d2988b
hex25c5ce92b257

41531504505431 has 2 divisors, whose sum is σ = 41531504505432. Its totient is φ = 41531504505430.

The previous prime is 41531504505427. The next prime is 41531504505433. The reversal of 41531504505431 is 13450540513514.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41531504505431 - 22 = 41531504505427 is a prime.

It is a super-2 number, since 2×415315045054312 (a number of 28 digits) contains 22 as substring.

Together with 41531504505433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41531504505433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20765752252715 + 20765752252716.

It is an arithmetic number, because the mean of its divisors is an integer number (20765752252716).

Almost surely, 241531504505431 is an apocalyptic number.

41531504505431 is a deficient number, since it is larger than the sum of its proper divisors (1).

41531504505431 is an equidigital number, since it uses as much as digits as its factorization.

41531504505431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360000, while the sum is 41.

The spelling of 41531504505431 in words is "forty-one trillion, five hundred thirty-one billion, five hundred four million, five hundred five thousand, four hundred thirty-one".