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41550121031 is a prime number
BaseRepresentation
bin100110101100100101…
…001000100001000111
310222020200212211210112
4212230211020201013
51140043312333111
631030551143235
73000436126046
oct465445104107
9128220784715
1041550121031
1116691a61a01
128077074b1b
133bc2273043
1420223da55d
151132b31e8b
hex9ac948847

41550121031 has 2 divisors, whose sum is σ = 41550121032. Its totient is φ = 41550121030.

The previous prime is 41550121009. The next prime is 41550121079. The reversal of 41550121031 is 13012105514.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 41550121031 - 26 = 41550120967 is a prime.

It is a super-2 number, since 2×415501210312 (a number of 22 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 41550120988 and 41550121006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41550151031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20775060515 + 20775060516.

It is an arithmetic number, because the mean of its divisors is an integer number (20775060516).

Almost surely, 241550121031 is an apocalyptic number.

41550121031 is a deficient number, since it is larger than the sum of its proper divisors (1).

41550121031 is an equidigital number, since it uses as much as digits as its factorization.

41550121031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 41550121031 its reverse (13012105514), we get a palindrome (54562226545).

The spelling of 41550121031 in words is "forty-one billion, five hundred fifty million, one hundred twenty-one thousand, thirty-one".