41636645441351 has 2 divisors, whose sum is σ = 41636645441352. Its totient is φ = 41636645441350.

The previous prime is 41636645441297. The next prime is 41636645441353. The reversal of 41636645441351 is 15314454663614.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41636645441351 is a prime.

It is a super-3 number, since 3×41636645441351³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 41636645441353, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 41636645441293 and 41636645441302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41636645441353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20818322720675 + 20818322720676.

It is an arithmetic number, because the mean of its divisors is an integer number (20818322720676).

Almost surely, 2^{41636645441351} is an apocalyptic number.

41636645441351 is a deficient number, since it is larger than the sum of its proper divisors (1).

41636645441351 is an equidigital number, since it uses as much as digits as its factorization.

41636645441351 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12441600, while the sum is 53.

The spelling of 41636645441351 in words is "forty-one trillion, six hundred thirty-six billion, six hundred forty-five million, four hundred forty-one thousand, three hundred fifty-one".