Base | Representation |
---|---|
bin | 101111110000101101000000… |
… | …1111100011111111110110101 |
3 | 2001002111010121222101201121001 |
4 | 1133201122001330133332311 |
5 | 420031041001432231240 |
6 | 4045255530514323301 |
7 | 154326645122553304 |
oct | 13741320174377665 |
9 | 2032433558351531 |
10 | 420110111211445 |
11 | 111950774592626 |
12 | 3b1501a2289531 |
13 | 150552a1099275 |
14 | 75a561b75843b |
15 | 3388064c2889a |
hex | 17e1681f1ffb5 |
420110111211445 has 8 divisors (see below), whose sum is σ = 511656493654944. Its totient is φ = 331071848835024.
The previous prime is 420110111211437. The next prime is 420110111211451. The reversal of 420110111211445 is 544112111011024.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 420110111211445 - 23 = 420110111211437 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 627030016399 + ... + 627030017068.
It is an arithmetic number, because the mean of its divisors is an integer number (63957061706868).
Almost surely, 2420110111211445 is an apocalyptic number.
It is an amenable number.
420110111211445 is a deficient number, since it is larger than the sum of its proper divisors (91546382443499).
420110111211445 is a wasteful number, since it uses less digits than its factorization.
420110111211445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1254060033539.
The product of its (nonzero) digits is 1280, while the sum is 28.
Adding to 420110111211445 its reverse (544112111011024), we get a palindrome (964222222222469).
The spelling of 420110111211445 in words is "four hundred twenty trillion, one hundred ten billion, one hundred eleven million, two hundred eleven thousand, four hundred forty-five".
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