Base | Representation |
---|---|
bin | 10011000110101101100000… |
… | …10111101110010110000111 |
3 | 12111202022101220010002000112 |
4 | 21203112300113232112013 |
5 | 21001311121214200320 |
6 | 225204021222303235 |
7 | 11564161241011562 |
oct | 1143266027562607 |
9 | 174668356102015 |
10 | 42012034131335 |
11 | 12428227019944 |
12 | 4866269287b1b |
13 | 1a59944083bb8 |
14 | a5357130d4d9 |
15 | 4ccc6945cec5 |
hex | 2635b05ee587 |
42012034131335 has 16 divisors (see below), whose sum is σ = 52284237458400. Its totient is φ = 32368934860416.
The previous prime is 42012034131317. The next prime is 42012034131349. The reversal of 42012034131335 is 53313143021024.
It is a cyclic number.
It is not a de Polignac number, because 42012034131335 - 214 = 42012034114951 is a prime.
It is a super-2 number, since 2×420120341313352 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 364851965 + ... + 364967094.
It is an arithmetic number, because the mean of its divisors is an integer number (3267764841150).
Almost surely, 242012034131335 is an apocalyptic number.
42012034131335 is a deficient number, since it is larger than the sum of its proper divisors (10272203327065).
42012034131335 is a wasteful number, since it uses less digits than its factorization.
42012034131335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 729819490.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 42012034131335 its reverse (53313143021024), we get a palindrome (95325177152359).
The spelling of 42012034131335 in words is "forty-two trillion, twelve billion, thirty-four million, one hundred thirty-one thousand, three hundred thirty-five".
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