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42013311541 is a prime number
BaseRepresentation
bin100111001000001100…
…000100001000110101
311000102222110100201121
4213020030010020311
51142020401432131
631144535023541
73015062153515
oct471014041065
9130388410647
1042013311541
11168aa467883
12818620abb1
133c6720a876
142067b2d845
15115d628911
hex9c8304235

42013311541 has 2 divisors, whose sum is σ = 42013311542. Its totient is φ = 42013311540.

The previous prime is 42013311479. The next prime is 42013311547. The reversal of 42013311541 is 14511331024.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24570562500 + 17442749041 = 156750^2 + 132071^2 .

It is a cyclic number.

It is not a de Polignac number, because 42013311541 - 215 = 42013278773 is a prime.

It is a super-2 number, since 2×420133115412 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (42013311547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21006655770 + 21006655771.

It is an arithmetic number, because the mean of its divisors is an integer number (21006655771).

Almost surely, 242013311541 is an apocalyptic number.

It is an amenable number.

42013311541 is a deficient number, since it is larger than the sum of its proper divisors (1).

42013311541 is an equidigital number, since it uses as much as digits as its factorization.

42013311541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 42013311541 its reverse (14511331024), we get a palindrome (56524642565).

The spelling of 42013311541 in words is "forty-two billion, thirteen million, three hundred eleven thousand, five hundred forty-one".