Base | Representation |
---|---|
bin | 100111001000001100… |
… | …000100001000110101 |
3 | 11000102222110100201121 |
4 | 213020030010020311 |
5 | 1142020401432131 |
6 | 31144535023541 |
7 | 3015062153515 |
oct | 471014041065 |
9 | 130388410647 |
10 | 42013311541 |
11 | 168aa467883 |
12 | 818620abb1 |
13 | 3c6720a876 |
14 | 2067b2d845 |
15 | 115d628911 |
hex | 9c8304235 |
42013311541 has 2 divisors, whose sum is σ = 42013311542. Its totient is φ = 42013311540.
The previous prime is 42013311479. The next prime is 42013311547. The reversal of 42013311541 is 14511331024.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 24570562500 + 17442749041 = 156750^2 + 132071^2 .
It is a cyclic number.
It is not a de Polignac number, because 42013311541 - 215 = 42013278773 is a prime.
It is a super-2 number, since 2×420133115412 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (42013311547) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21006655770 + 21006655771.
It is an arithmetic number, because the mean of its divisors is an integer number (21006655771).
Almost surely, 242013311541 is an apocalyptic number.
It is an amenable number.
42013311541 is a deficient number, since it is larger than the sum of its proper divisors (1).
42013311541 is an equidigital number, since it uses as much as digits as its factorization.
42013311541 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 42013311541 its reverse (14511331024), we get a palindrome (56524642565).
The spelling of 42013311541 in words is "forty-two billion, thirteen million, three hundred eleven thousand, five hundred forty-one".
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