Base | Representation |
---|---|
bin | 111101001000111110011… |
… | …010010101001101011101 |
3 | 112212122212111201202212111 |
4 | 331020332122111031131 |
5 | 1022314210411334001 |
6 | 12534053132234021 |
7 | 612356465066623 |
oct | 75107632251535 |
9 | 15778774652774 |
10 | 4201525105501 |
11 | 137a947430139 |
12 | 57a34a30b911 |
13 | 24628208a0a9 |
14 | 1074d7bbb513 |
15 | 74458287851 |
hex | 3d23e69535d |
4201525105501 has 16 divisors (see below), whose sum is σ = 4389738997248. Its totient is φ = 4013776030000.
The previous prime is 4201525105493. The next prime is 4201525105549. The reversal of 4201525105501 is 1055015251024.
It is a cyclic number.
It is not a de Polignac number, because 4201525105501 - 23 = 4201525105493 is a prime.
It is a super-3 number, since 3×42015251055013 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4201525165501) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 59602326 + ... + 59672776.
It is an arithmetic number, because the mean of its divisors is an integer number (274358687328).
Almost surely, 24201525105501 is an apocalyptic number.
It is an amenable number.
4201525105501 is a deficient number, since it is larger than the sum of its proper divisors (188213891747).
4201525105501 is a wasteful number, since it uses less digits than its factorization.
4201525105501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73712.
The product of its (nonzero) digits is 10000, while the sum is 31.
The spelling of 4201525105501 in words is "four trillion, two hundred one billion, five hundred twenty-five million, one hundred five thousand, five hundred one".
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