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42042213525371 is a prime number
BaseRepresentation
bin10011000111100101101110…
…01100111110011101111011
312111212012022010222010202012
421203302313030332131323
521002304423130302441
6225225532023400135
711566310146433243
oct1143626714763573
9174765263863665
1042042213525371
111243a003551304
1248700902b304b
131a5c74366a0c7
14a54bd54d4b23
154cd933bc09eb
hex263cb733e77b

42042213525371 has 2 divisors, whose sum is σ = 42042213525372. Its totient is φ = 42042213525370.

The previous prime is 42042213525271. The next prime is 42042213525373. The reversal of 42042213525371 is 17352531224024.

Adding to 42042213525371 its reverse (17352531224024), we get a palindrome (59394744749395).

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 42042213525371 - 210 = 42042213524347 is a prime.

It is a super-2 number, since 2×420422135253712 (a number of 28 digits) contains 22 as substring.

Together with 42042213525373, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (42042213525373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21021106762685 + 21021106762686.

It is an arithmetic number, because the mean of its divisors is an integer number (21021106762686).

Almost surely, 242042213525371 is an apocalyptic number.

42042213525371 is a deficient number, since it is larger than the sum of its proper divisors (1).

42042213525371 is an equidigital number, since it uses as much as digits as its factorization.

42042213525371 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 403200, while the sum is 41.

The spelling of 42042213525371 in words is "forty-two trillion, forty-two billion, two hundred thirteen million, five hundred twenty-five thousand, three hundred seventy-one".