Base | Representation |
---|---|
bin | 100111001001111110… |
… | …100111010101001111 |
3 | 11000112001221222011212 |
4 | 213021332213111033 |
5 | 1142101043340421 |
6 | 31151530405035 |
7 | 3015605331413 |
oct | 471176472517 |
9 | 130461858155 |
10 | 42043340111 |
11 | 16915407783 |
12 | 819429077b |
13 | 3c704c2856 |
14 | 206bb08d43 |
15 | 11610aae5b |
hex | 9c9fa754f |
42043340111 has 4 divisors (see below), whose sum is σ = 42048109824. Its totient is φ = 42038570400.
The previous prime is 42043340089. The next prime is 42043340117. The reversal of 42043340111 is 11104334024.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-42043340111 is a prime.
It is a super-3 number, since 3×420433401113 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (42043340117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2371610 + ... + 2389271.
It is an arithmetic number, because the mean of its divisors is an integer number (10512027456).
Almost surely, 242043340111 is an apocalyptic number.
42043340111 is a deficient number, since it is larger than the sum of its proper divisors (4769713).
42043340111 is an equidigital number, since it uses as much as digits as its factorization.
42043340111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4769712.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 42043340111 its reverse (11104334024), we get a palindrome (53147674135).
The spelling of 42043340111 in words is "forty-two billion, forty-three million, three hundred forty thousand, one hundred eleven".
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