Base | Representation |
---|---|
bin | 10011001001101001100110… |
… | …01000000111110011101111 |
3 | 12112002222001012222121011000 |
4 | 21210310303020013303233 |
5 | 21004434422044320211 |
6 | 225322241202531343 |
7 | 11604364461430602 |
oct | 1144646310076357 |
9 | 175088035877130 |
10 | 42113012104431 |
11 | 124670344a3674 |
12 | 488194a666b53 |
13 | 1a6631738a938 |
14 | a583d01c6339 |
15 | 4d06c9477656 |
hex | 264d33207cef |
42113012104431 has 16 divisors (see below), whose sum is σ = 66059626831200. Its totient is φ = 26423850731904.
The previous prime is 42113012104349. The next prime is 42113012104451. The reversal of 42113012104431 is 13440121031124.
It is a happy number.
42113012104431 is a `hidden beast` number, since 4 + 2 + 1 + 1 + 3 + 0 + 1 + 210 + 443 + 1 = 666.
It is not a de Polignac number, because 42113012104431 - 29 = 42113012103919 is a prime.
It is a super-2 number, since 2×421130121044312 (a number of 28 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 42113012104395 and 42113012104404.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (42113012104451) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 45874740396 + ... + 45874741313.
It is an arithmetic number, because the mean of its divisors is an integer number (4128726676950).
Almost surely, 242113012104431 is an apocalyptic number.
42113012104431 is a deficient number, since it is larger than the sum of its proper divisors (23946614726769).
42113012104431 is a wasteful number, since it uses less digits than its factorization.
42113012104431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 91749481735 (or 91749481729 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 42113012104431 its reverse (13440121031124), we get a palindrome (55553133135555).
The spelling of 42113012104431 in words is "forty-two trillion, one hundred thirteen billion, twelve million, one hundred four thousand, four hundred thirty-one".
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