Base | Representation |
---|---|
bin | 10011001001110110101100… |
… | …01110000101001100111111 |
3 | 12112010122012020110100211011 |
4 | 21210323112032011030333 |
5 | 21010043322042221002 |
6 | 225325403014140051 |
7 | 11605033636660663 |
oct | 1144732616051477 |
9 | 175118166410734 |
10 | 42120043320127 |
11 | 1246a012429033 |
12 | 4883191351627 |
13 | 1a66b97ca2cb6 |
14 | a58899d4a8a3 |
15 | 4d098b8aa8d7 |
hex | 264ed638533f |
42120043320127 has 2 divisors, whose sum is σ = 42120043320128. Its totient is φ = 42120043320126.
The previous prime is 42120043320097. The next prime is 42120043320169. The reversal of 42120043320127 is 72102334002124.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 42120043320127 - 211 = 42120043318079 is a prime.
It is a super-3 number, since 3×421200433201273 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (42120043320427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21060021660063 + 21060021660064.
It is an arithmetic number, because the mean of its divisors is an integer number (21060021660064).
Almost surely, 242120043320127 is an apocalyptic number.
42120043320127 is a deficient number, since it is larger than the sum of its proper divisors (1).
42120043320127 is an equidigital number, since it uses as much as digits as its factorization.
42120043320127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 31.
The spelling of 42120043320127 in words is "forty-two trillion, one hundred twenty billion, forty-three million, three hundred twenty thousand, one hundred twenty-seven".
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