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4215124230131 is a prime number
BaseRepresentation
bin111101010101101000111…
…110110111111111110011
3112220221222020212212211002
4331111220332313333303
51023030033300331011
612544222404512215
7613350464536403
oct75255076677763
915827866785732
104215124230131
111385695815811
12580b046ab66b
1324763b60c0b9
14108027d42803
15749a20d2c3b
hex3d568fb7ff3

4215124230131 has 2 divisors, whose sum is σ = 4215124230132. Its totient is φ = 4215124230130.

The previous prime is 4215124230101. The next prime is 4215124230133. The reversal of 4215124230131 is 1310324215124.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4215124230131 - 222 = 4215120035827 is a prime.

It is a super-2 number, since 2×42151242301312 (a number of 26 digits) contains 22 as substring.

Together with 4215124230133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4215124230094 and 4215124230103.

It is not a weakly prime, because it can be changed into another prime (4215124230133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2107562115065 + 2107562115066.

It is an arithmetic number, because the mean of its divisors is an integer number (2107562115066).

Almost surely, 24215124230131 is an apocalyptic number.

4215124230131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4215124230131 is an equidigital number, since it uses as much as digits as its factorization.

4215124230131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 4215124230131 its reverse (1310324215124), we get a palindrome (5525448445255).

The spelling of 4215124230131 in words is "four trillion, two hundred fifteen billion, one hundred twenty-four million, two hundred thirty thousand, one hundred thirty-one".