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423132231433 is a prime number
BaseRepresentation
bin1100010100001001010…
…01010111011100001001
31111110011210221111000011
412022010221113130021
523413033322401213
6522215000111521
742366416423662
oct6120451273411
91443153844004
10423132231433
111534a412823a
126a00a1655a1
1330b93c17852
14166a0472369
15b01762803d
hex6284a57709

423132231433 has 2 divisors, whose sum is σ = 423132231434. Its totient is φ = 423132231432.

The previous prime is 423132231311. The next prime is 423132231449. The reversal of 423132231433 is 334132231324.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 284902940169 + 138229291264 = 533763^2 + 371792^2 .

It is a cyclic number.

It is not a de Polignac number, because 423132231433 - 233 = 414542296841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 423132231395 and 423132231404.

It is not a weakly prime, because it can be changed into another prime (423132231833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 211566115716 + 211566115717.

It is an arithmetic number, because the mean of its divisors is an integer number (211566115717).

Almost surely, 2423132231433 is an apocalyptic number.

It is an amenable number.

423132231433 is a deficient number, since it is larger than the sum of its proper divisors (1).

423132231433 is an equidigital number, since it uses as much as digits as its factorization.

423132231433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31104, while the sum is 31.

Adding to 423132231433 its reverse (334132231324), we get a palindrome (757264462757).

The spelling of 423132231433 in words is "four hundred twenty-three billion, one hundred thirty-two million, two hundred thirty-one thousand, four hundred thirty-three".