Base | Representation |
---|---|
bin | 1100010100100011110… |
… | …10011100010111111111 |
3 | 1111110202022202202000021 |
4 | 12022101322130113333 |
5 | 23414012312440103 |
6 | 522253030513011 |
7 | 42405061345432 |
oct | 6122172342777 |
9 | 1443668682007 |
10 | 423354811903 |
11 | 1535a8833241 |
12 | 6a070805767 |
13 | 30bcb07997a |
14 | 166c1c51819 |
15 | b02be42bbd |
hex | 6291e9c5ff |
423354811903 has 2 divisors, whose sum is σ = 423354811904. Its totient is φ = 423354811902.
The previous prime is 423354811877. The next prime is 423354811907. The reversal of 423354811903 is 309118453324.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-423354811903 is a prime.
It is a super-2 number, since 2×4233548119032 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 423354811903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (423354811907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 211677405951 + 211677405952.
It is an arithmetic number, because the mean of its divisors is an integer number (211677405952).
Almost surely, 2423354811903 is an apocalyptic number.
423354811903 is a deficient number, since it is larger than the sum of its proper divisors (1).
423354811903 is an equidigital number, since it uses as much as digits as its factorization.
423354811903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 423354811903 in words is "four hundred twenty-three billion, three hundred fifty-four million, eight hundred eleven thousand, nine hundred three".
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