Base | Representation |
---|---|
bin | 110000001001011110001000… |
… | …0010110101111001011010111 |
3 | 2001112112112221211020011121012 |
4 | 1200102330100112233023113 |
5 | 421002323401311140120 |
6 | 4100423410455442435 |
7 | 155130612365551646 |
oct | 14022742026571327 |
9 | 2045475854204535 |
10 | 423514114552535 |
11 | 112a43366747056 |
12 | 3b5bba5808641b |
13 | 15241295758886 |
14 | 768229a39735d |
15 | 33e689254b1c5 |
hex | 1812f105af2d7 |
423514114552535 has 4 divisors (see below), whose sum is σ = 508216937463048. Its totient is φ = 338811291642024.
The previous prime is 423514114552513. The next prime is 423514114552553. The reversal of 423514114552535 is 535255411415324.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 423514114552535 - 232 = 423509819585239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42351411455249 + ... + 42351411455258.
It is an arithmetic number, because the mean of its divisors is an integer number (127054234365762).
Almost surely, 2423514114552535 is an apocalyptic number.
423514114552535 is a deficient number, since it is larger than the sum of its proper divisors (84702822910513).
423514114552535 is an equidigital number, since it uses as much as digits as its factorization.
423514114552535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84702822910512.
The product of its digits is 7200000, while the sum is 50.
Adding to 423514114552535 its reverse (535255411415324), we get a palindrome (958769525967859).
The spelling of 423514114552535 in words is "four hundred twenty-three trillion, five hundred fourteen billion, one hundred fourteen million, five hundred fifty-two thousand, five hundred thirty-five".
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