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424130646131 is a prime number
BaseRepresentation
bin1100010110000000010…
…10000001000001110011
31111112202101122012111022
412023000022001001303
523422104421134011
6522502023410055
742433232003003
oct6130012010163
91445671565438
10424130646131
11153966768a55
126a2485b392b
1330cc2a1b28a
1416756cca003
15b0750e48db
hex62c0281073

424130646131 has 2 divisors, whose sum is σ = 424130646132. Its totient is φ = 424130646130.

The previous prime is 424130646101. The next prime is 424130646133. The reversal of 424130646131 is 131646031424.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 424130646131 - 238 = 149252739187 is a prime.

It is a super-2 number, since 2×4241306461312 (a number of 24 digits) contains 22 as substring.

Together with 424130646133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 424130646091 and 424130646100.

It is not a weakly prime, because it can be changed into another prime (424130646133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 212065323065 + 212065323066.

It is an arithmetic number, because the mean of its divisors is an integer number (212065323066).

Almost surely, 2424130646131 is an apocalyptic number.

424130646131 is a deficient number, since it is larger than the sum of its proper divisors (1).

424130646131 is an equidigital number, since it uses as much as digits as its factorization.

424130646131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 35.

Adding to 424130646131 its reverse (131646031424), we get a palindrome (555776677555).

The spelling of 424130646131 in words is "four hundred twenty-four billion, one hundred thirty million, six hundred forty-six thousand, one hundred thirty-one".