Base | Representation |
---|---|
bin | 10011010010011010110100… |
… | …01011111000100000110111 |
3 | 12120011202202112202021221100 |
4 | 21221031122023320200313 |
5 | 21024404004132100003 |
6 | 230112511204021143 |
7 | 11635222160642505 |
oct | 1151153213704067 |
9 | 176152675667840 |
10 | 42414315112503 |
11 | 125728a0162144 |
12 | 49102183917b3 |
13 | 1a88864138729 |
14 | a68c143cd675 |
15 | 4d846121cba3 |
hex | 26935a2f8837 |
42414315112503 has 12 divisors (see below), whose sum is σ = 62689892104840. Its totient is φ = 27618623793936.
The previous prime is 42414315112459. The next prime is 42414315112513. The reversal of 42414315112503 is 30521151341424.
42414315112503 is a `hidden beast` number, since 4 + 2 + 4 + 1 + 4 + 31 + 5 + 112 + 503 = 666.
42414315112503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 42414315112503 - 29 = 42414315111991 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (42414315112513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 54798856348 + ... + 54798857121.
Almost surely, 242414315112503 is an apocalyptic number.
42414315112503 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
42414315112503 is a deficient number, since it is larger than the sum of its proper divisors (20275576992337).
42414315112503 is a wasteful number, since it uses less digits than its factorization.
42414315112503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 109597713518 (or 109597713515 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 36.
Adding to 42414315112503 its reverse (30521151341424), we get a palindrome (72935466453927).
The spelling of 42414315112503 in words is "forty-two trillion, four hundred fourteen billion, three hundred fifteen million, one hundred twelve thousand, five hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •