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42605065141 = 45499365809
BaseRepresentation
bin100111101011011101…
…011011001110110101
311001222012221120001121
4213223131123032311
51144223344041031
631323354223541
73035536035622
oct475335331665
9131865846047
1042605065141
11170834a3041
128310424bb1
13402c9a9b22
1420c256b349
151195568011
hex9eb75b3b5

42605065141 has 4 divisors (see below), whose sum is σ = 42614435500. Its totient is φ = 42595694784.

The previous prime is 42605065067. The next prime is 42605065159. The reversal of 42605065141 is 14156050624.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 39225386916 + 3379678225 = 198054^2 + 58135^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-42605065141 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 42605065097 and 42605065106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (42605069141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4678356 + ... + 4687453.

It is an arithmetic number, because the mean of its divisors is an integer number (10653608875).

Almost surely, 242605065141 is an apocalyptic number.

It is an amenable number.

42605065141 is a deficient number, since it is larger than the sum of its proper divisors (9370359).

42605065141 is an equidigital number, since it uses as much as digits as its factorization.

42605065141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9370358.

The product of its (nonzero) digits is 28800, while the sum is 34.

The spelling of 42605065141 in words is "forty-two billion, six hundred five million, sixty-five thousand, one hundred forty-one".

Divisors: 1 4549 9365809 42605065141