4264341335047 has 2 divisors, whose sum is σ = 4264341335048. Its totient is φ = 4264341335046.

The previous prime is 4264341335017. The next prime is 4264341335077. The reversal of 4264341335047 is 7405331434624.

It is a balanced prime because it is at equal distance from previous prime (4264341335017) and next prime (4264341335077).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4264341335047 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4264341334988 and 4264341335006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4264341335017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2132170667523 + 2132170667524.

It is an arithmetic number, because the mean of its divisors is an integer number (2132170667524).

Almost surely, 2^{4264341335047} is an apocalyptic number.

4264341335047 is a deficient number, since it is larger than the sum of its proper divisors (1).

4264341335047 is an equidigital number, since it uses as much as digits as its factorization.

4264341335047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2903040, while the sum is 46.

The spelling of 4264341335047 in words is "four trillion, two hundred sixty-four billion, three hundred forty-one million, three hundred thirty-five thousand, forty-seven".