Base | Representation |
---|---|
bin | 111110000011011110100… |
… | …011001110110101100001 |
3 | 120002200000021112212202112 |
4 | 332003132203032311201 |
5 | 1024331332340213033 |
6 | 13023002242125105 |
7 | 620042232200246 |
oct | 76033643166541 |
9 | 16080007485675 |
10 | 4264341335393 |
11 | 13a4551570417 |
12 | 58a55b350795 |
13 | 24c1831078a9 |
14 | 10a5766bb5cd |
15 | 75dd2d7dc48 |
hex | 3e0de8ced61 |
4264341335393 has 4 divisors (see below), whose sum is σ = 4268352946368. Its totient is φ = 4260329724420.
The previous prime is 4264341335389. The next prime is 4264341335431. The reversal of 4264341335393 is 3935331434624.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 4264341335393 - 22 = 4264341335389 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4264341335593) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2005803893 + ... + 2005806018.
It is an arithmetic number, because the mean of its divisors is an integer number (1067088236592).
Almost surely, 24264341335393 is an apocalyptic number.
It is an amenable number.
4264341335393 is a deficient number, since it is larger than the sum of its proper divisors (4011610975).
4264341335393 is a wasteful number, since it uses less digits than its factorization.
4264341335393 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4011610974.
The product of its digits is 8398080, while the sum is 50.
The spelling of 4264341335393 in words is "four trillion, two hundred sixty-four billion, three hundred forty-one million, three hundred thirty-five thousand, three hundred ninety-three".
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