Base | Representation |
---|---|
bin | 1100011101011010110… |
… | …01000001010111110111 |
3 | 1111221000202221221120221 |
4 | 12032231121001113313 |
5 | 24003232324424040 |
6 | 524401003435211 |
7 | 42633661405351 |
oct | 6165531012767 |
9 | 1457022857527 |
10 | 428110779895 |
11 | 1556194133a7 |
12 | 6ab79525b07 |
13 | 314a84a5406 |
14 | 16a1374c0d1 |
15 | b20974374a |
hex | 63ad6415f7 |
428110779895 has 4 divisors (see below), whose sum is σ = 513732935880. Its totient is φ = 342488623912.
The previous prime is 428110779869. The next prime is 428110779913. The reversal of 428110779895 is 598977011824.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 428110779895 - 211 = 428110777847 is a prime.
It is a super-2 number, since 2×4281107798952 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42811077985 + ... + 42811077994.
It is an arithmetic number, because the mean of its divisors is an integer number (128433233970).
Almost surely, 2428110779895 is an apocalyptic number.
428110779895 is a deficient number, since it is larger than the sum of its proper divisors (85622155985).
428110779895 is an equidigital number, since it uses as much as digits as its factorization.
428110779895 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85622155984.
The product of its (nonzero) digits is 10160640, while the sum is 61.
The spelling of 428110779895 in words is "four hundred twenty-eight billion, one hundred ten million, seven hundred seventy-nine thousand, eight hundred ninety-five".
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