Base | Representation |
---|---|
bin | 1100100001000010100… |
… | …10001011111001001011 |
3 | 1112010001021121221010122 |
4 | 12100201102023321023 |
5 | 24021223104120120 |
6 | 525321542133455 |
7 | 43033111263365 |
oct | 6204122137113 |
9 | 1463037557118 |
10 | 430055145035 |
11 | 156426a1073a |
12 | 6b42072128b |
13 | 31728270629 |
14 | 16b59a83d35 |
15 | b2c02b6a25 |
hex | 642148be4b |
430055145035 has 4 divisors (see below), whose sum is σ = 516066174048. Its totient is φ = 344044116024.
The previous prime is 430055145017. The next prime is 430055145089. The reversal of 430055145035 is 530541550034.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 430055145035 - 26 = 430055144971 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 430055144986 and 430055145004.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43005514499 + ... + 43005514508.
It is an arithmetic number, because the mean of its divisors is an integer number (129016543512).
Almost surely, 2430055145035 is an apocalyptic number.
430055145035 is a deficient number, since it is larger than the sum of its proper divisors (86011029013).
430055145035 is an equidigital number, since it uses as much as digits as its factorization.
430055145035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86011029012.
The product of its (nonzero) digits is 90000, while the sum is 35.
Adding to 430055145035 its reverse (530541550034), we get a palindrome (960596695069).
The spelling of 430055145035 in words is "four hundred thirty billion, fifty-five million, one hundred forty-five thousand, thirty-five".
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