430100113001231 has 4 divisors (see below), whose sum is σ = 448800117914352. Its totient is φ = 411400108088112.

The previous prime is 430100113001219. The next prime is 430100113001239. The reversal of 430100113001231 is 132100311001034.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-430100113001231 is a prime.

It is a super-2 number, since 2×430100113001231² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (430100113001239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9350002456526 + ... + 9350002456571.

It is an arithmetic number, because the mean of its divisors is an integer number (112200029478588).

Almost surely, 2^{430100113001231} is an apocalyptic number.

430100113001231 is a deficient number, since it is larger than the sum of its proper divisors (18700004913121).

430100113001231 is a wasteful number, since it uses less digits than its factorization.

430100113001231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18700004913120.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 430100113001231 its reverse (132100311001034), we get a palindrome (562200424002265).

The spelling of 430100113001231 in words is "four hundred thirty trillion, one hundred billion, one hundred thirteen million, one thousand, two hundred thirty-one".