43010014013 has 2 divisors, whose sum is σ = 43010014014. Its totient is φ = 43010014012.

The previous prime is 43010013997. The next prime is 43010014109. The reversal of 43010014013 is 31041001034.

43010014013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26537061604 + 16472952409 = 162902^2 + 128347^2 .

It is a cyclic number.

It is not a de Polignac number, because 43010014013 - 2⁴ = 43010013997 is a prime.

It is a super-2 number, since 2×43010014013² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43010013982 and 43010014000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43010014213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21505007006 + 21505007007.

It is an arithmetic number, because the mean of its divisors is an integer number (21505007007).

Almost surely, 2^43010014013 is an apocalyptic number.

It is an amenable number.

43010014013 is a deficient number, since it is larger than the sum of its proper divisors (1).

43010014013 is an equidigital number, since it uses as much as digits as its factorization.

43010014013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 43010014013 its reverse (31041001034), we get a palindrome (74051015047).

The spelling of 43010014013 in words is "forty-three billion, ten million, fourteen thousand, thirteen".