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43010031141221 is a prime number
BaseRepresentation
bin10011100011110000011011…
…01000001100000101100101
312122021201102000120001121112
421301320031220030011211
521114134020433004341
6231250311401554405
712026241444433364
oct1161701550140545
9178251360501545
1043010031141221
11127824a7345701
1249a77704a5a05
131accaa0399391
14a899a771d7db
154e8bc9e20aeb
hex271e0da0c165

43010031141221 has 2 divisors, whose sum is σ = 43010031141222. Its totient is φ = 43010031141220.

The previous prime is 43010031141173. The next prime is 43010031141227. The reversal of 43010031141221 is 12214113001034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36419849032996 + 6590182108225 = 6034886^2 + 2567135^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43010031141221 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43010031141227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21505015570610 + 21505015570611.

It is an arithmetic number, because the mean of its divisors is an integer number (21505015570611).

Almost surely, 243010031141221 is an apocalyptic number.

It is an amenable number.

43010031141221 is a deficient number, since it is larger than the sum of its proper divisors (1).

43010031141221 is an equidigital number, since it uses as much as digits as its factorization.

43010031141221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 43010031141221 its reverse (12214113001034), we get a palindrome (55224144142255).

The spelling of 43010031141221 in words is "forty-three trillion, ten billion, thirty-one million, one hundred forty-one thousand, two hundred twenty-one".