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430113142101 = 3143371047367
BaseRepresentation
bin1100100001001001011…
…11011011010101010101
31112010012022202111011010
412100210233123111111
524021332431021401
6525331413202433
743034414246136
oct6204457332525
91463168674133
10430113142101
111564567237a5
126b438030419
1331737298a16
1416b6365dc8d
15b2c5420ed6
hex6424bdb555

430113142101 has 4 divisors (see below), whose sum is σ = 573484189472. Its totient is φ = 286742094732.

The previous prime is 430113142093. The next prime is 430113142117. The reversal of 430113142101 is 101241311034.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 430113142101 - 23 = 430113142093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (430113142301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71685523681 + ... + 71685523686.

It is an arithmetic number, because the mean of its divisors is an integer number (143371047368).

Almost surely, 2430113142101 is an apocalyptic number.

It is an amenable number.

430113142101 is a deficient number, since it is larger than the sum of its proper divisors (143371047371).

430113142101 is a wasteful number, since it uses less digits than its factorization.

430113142101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143371047370.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 430113142101 its reverse (101241311034), we get a palindrome (531354453135).

The spelling of 430113142101 in words is "four hundred thirty billion, one hundred thirteen million, one hundred forty-two thousand, one hundred one".

Divisors: 1 3 143371047367 430113142101