Base | Representation |
---|---|
bin | 1100100001001010010… |
… | …10011001111001010101 |
3 | 1112010012211001210010001 |
4 | 12100211022121321111 |
5 | 24021341233322401 |
6 | 525332224531301 |
7 | 43034531332204 |
oct | 6204512317125 |
9 | 1463184053101 |
10 | 430120214101 |
11 | 15645a714026 |
12 | 6b43a480b31 |
13 | 317388a3936 |
14 | 16b6458123b |
15 | b2c5d6b601 |
hex | 6425299e55 |
430120214101 has 4 divisors (see below), whose sum is σ = 431833840704. Its totient is φ = 428406587500.
The previous prime is 430120214093. The next prime is 430120214107. The reversal of 430120214101 is 101412021034.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 430120214101 - 23 = 430120214093 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (430120214107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 856812925 + ... + 856813426.
It is an arithmetic number, because the mean of its divisors is an integer number (107958460176).
Almost surely, 2430120214101 is an apocalyptic number.
It is an amenable number.
430120214101 is a deficient number, since it is larger than the sum of its proper divisors (1713626603).
430120214101 is a wasteful number, since it uses less digits than its factorization.
430120214101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1713626602.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 430120214101 its reverse (101412021034), we get a palindrome (531532235135).
The spelling of 430120214101 in words is "four hundred thirty billion, one hundred twenty million, two hundred fourteen thousand, one hundred one".
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