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430130505541 = 1139102773231
BaseRepresentation
bin1100100001001011100…
…01101010011101000101
31112010020112102122022111
412100211301222131011
524021401402134131
6525333233301021
743035014654332
oct6204561523505
91463215378274
10430130505541
11156465503150
126b441a04771
133173aa68049
1416b65a9d989
15b2c6c00ab1
hex6425c6a745

430130505541 has 4 divisors (see below), whose sum is σ = 469233278784. Its totient is φ = 391027732300.

The previous prime is 430130505529. The next prime is 430130505587. The reversal of 430130505541 is 145505031034.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 430130505541 - 29 = 430130505029 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (430130505241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19551386605 + ... + 19551386626.

It is an arithmetic number, because the mean of its divisors is an integer number (117308319696).

Almost surely, 2430130505541 is an apocalyptic number.

It is an amenable number.

430130505541 is a deficient number, since it is larger than the sum of its proper divisors (39102773243).

430130505541 is a wasteful number, since it uses less digits than its factorization.

430130505541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39102773242.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 430130505541 its reverse (145505031034), we get a palindrome (575635536575).

The spelling of 430130505541 in words is "four hundred thirty billion, one hundred thirty million, five hundred five thousand, five hundred forty-one".

Divisors: 1 11 39102773231 430130505541