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43013341011143 is a prime number
BaseRepresentation
bin10011100011110110100101…
…11010010101110011000111
312122022000221200122212120102
421301323102322111303013
521114212310244324033
6231252020035554315
712026416455034046
oct1161732272256307
9178260850585512
1043013341011143
1112783945710998
1249a8334a5b99b
131b001aa025ca9
14a89bdd14855d
154e8d207c2de8
hex271ed2e95cc7

43013341011143 has 2 divisors, whose sum is σ = 43013341011144. Its totient is φ = 43013341011142.

The previous prime is 43013341011089. The next prime is 43013341011197. The reversal of 43013341011143 is 34111014331034.

It is a balanced prime because it is at equal distance from previous prime (43013341011089) and next prime (43013341011197).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43013341011143 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43013341014143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21506670505571 + 21506670505572.

It is an arithmetic number, because the mean of its divisors is an integer number (21506670505572).

Almost surely, 243013341011143 is an apocalyptic number.

43013341011143 is a deficient number, since it is larger than the sum of its proper divisors (1).

43013341011143 is an equidigital number, since it uses as much as digits as its factorization.

43013341011143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 43013341011143 its reverse (34111014331034), we get a palindrome (77124355342177).

The spelling of 43013341011143 in words is "forty-three trillion, thirteen billion, three hundred forty-one million, eleven thousand, one hundred forty-three".