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4302342304031 is a prime number
BaseRepresentation
bin111110100110110111100…
…101011011000100011111
3120020022002122002002202102
4332212313211123010133
51030442144112212111
613052245130515315
7622556024122262
oct76466745330437
916208078062672
104302342304031
111409682083622
125959a5895b3b
1325292ac91955
1410c33d5a2cd9
1576da90e513b
hex3e9b795b11f

4302342304031 has 2 divisors, whose sum is σ = 4302342304032. Its totient is φ = 4302342304030.

The previous prime is 4302342303997. The next prime is 4302342304033. The reversal of 4302342304031 is 1304032432034.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4302342304031 - 26 = 4302342303967 is a prime.

It is a super-2 number, since 2×43023423040312 (a number of 26 digits) contains 22 as substring.

Together with 4302342304033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4302342303985 and 4302342304003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4302342304033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2151171152015 + 2151171152016.

It is an arithmetic number, because the mean of its divisors is an integer number (2151171152016).

Almost surely, 24302342304031 is an apocalyptic number.

4302342304031 is a deficient number, since it is larger than the sum of its proper divisors (1).

4302342304031 is an equidigital number, since it uses as much as digits as its factorization.

4302342304031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 29.

Adding to 4302342304031 its reverse (1304032432034), we get a palindrome (5606374736065).

The spelling of 4302342304031 in words is "four trillion, three hundred two billion, three hundred forty-two million, three hundred four thousand, thirty-one".