Base | Representation |
---|---|
bin | 1100100001100011011… |
… | …11011001111001000000 |
3 | 1112010202112011000020002 |
4 | 12100301233121321000 |
5 | 24022304244140000 |
6 | 525405203535132 |
7 | 43043003121104 |
oct | 6206157317100 |
9 | 1463675130202 |
10 | 430331240000 |
11 | 1565588479a2 |
12 | 6b49908a4a8 |
13 | 3177051b72c |
14 | 16b845d3904 |
15 | b2d96528d5 |
hex | 6431bd9e40 |
430331240000 has 70 divisors (see below), whose sum is σ = 1067081716734. Its totient is φ = 172132480000.
The previous prime is 430331239997. The next prime is 430331240011. The reversal of 430331240000 is 42133034.
It can be written as a sum of positive squares in 5 ways, for example, as 263324975104 + 167006264896 = 513152^2 + 408664^2 .
It is a super-2 number, since 2×4303312400002 (a number of 24 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 5339141 + ... + 5419140.
Almost surely, 2430331240000 is an apocalyptic number.
430331240000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
430331240000 is an abundant number, since it is smaller than the sum of its proper divisors (636750476734).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
430331240000 is an equidigital number, since it uses as much as digits as its factorization.
430331240000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10758313 (or 10758288 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 20.
Adding to 430331240000 its reverse (42133034), we get a palindrome (430373373034).
The spelling of 430331240000 in words is "four hundred thirty billion, three hundred thirty-one million, two hundred forty thousand".
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