Base | Representation |
---|---|
bin | 111110101000011011001… |
… | …110011111001101101101 |
3 | 120020110102010200201202021 |
4 | 332220123032133031231 |
5 | 1031004110041411133 |
6 | 13053123045230141 |
7 | 622645323325231 |
oct | 76503316371555 |
9 | 16213363621667 |
10 | 4304014013293 |
11 | 140a35a783525 |
12 | 596191702351 |
13 | 252b36414227 |
14 | 10c45b6025c1 |
15 | 76e55c5b52d |
hex | 3ea1b39f36d |
4304014013293 has 2 divisors, whose sum is σ = 4304014013294. Its totient is φ = 4304014013292.
The previous prime is 4304014013291. The next prime is 4304014013447. The reversal of 4304014013293 is 3923104104034.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4086696747364 + 217317265929 = 2021558^2 + 466173^2 .
It is a cyclic number.
It is not a de Polignac number, because 4304014013293 - 21 = 4304014013291 is a prime.
Together with 4304014013291, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4304014013291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2152007006646 + 2152007006647.
It is an arithmetic number, because the mean of its divisors is an integer number (2152007006647).
Almost surely, 24304014013293 is an apocalyptic number.
It is an amenable number.
4304014013293 is a deficient number, since it is larger than the sum of its proper divisors (1).
4304014013293 is an equidigital number, since it uses as much as digits as its factorization.
4304014013293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 34.
The spelling of 4304014013293 in words is "four trillion, three hundred four billion, fourteen million, thirteen thousand, two hundred ninety-three".
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